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Do Now: Pass out calculators. 1. Compare and contrast factoring: 6x 2 – x – 2 with factoring x 2 – x – 2 Factor both of the problems above. Write a few sentences explaining the similarities and differences about the process of factoring each.

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Do Now: Pass out calculators.

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Objective: To factor polynomials completely.

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Factor out a common binomial EXAMPLE 1 2x(x + 4) – 3(x + 4) a. SOLUTION 3y 2 (y – 2) + 5(2 – y) b. 2x(x + 4) – 3(x + 4) = (x + 4)(2x – 3) a. The binomials y – 2 and 2 – y are opposites. Factor – 1 from 2 – y to obtain a common binomial factor. b. 3y 2 (y – 2) + 5(2 – y) = 3y 2 (y – 2) – 5(y – 2) = (y – 2)(3y 2 – 5) Factor – 1 from ( 2 – y ). Distributive property Factor the expression.

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Factor by grouping EXAMPLE 2 x 3 + 3x 2 + 5x + 15. a y 2 + y + yx + x b. SOLUTION = x 2 (x + 3) + 5(x + 3) = (x + 3)(x 2 + 5) x 3 + 3x 2 + 5x + 15 = (x 3 + 3x 2 ) + (5x + 15) a. y 2 + y + yx + x = (y 2 + y) + (yx + x) b. = y(y + 1) + x(y + 1) = (y + 1)(y + x) Group terms. Factor each group. Distributive property Group terms. Factor each group. Distributive property Factor the polynomial.

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Factor by grouping EXAMPLE 3 Factor 6 + 2x. x3x3 – 3x23x2 – SOLUTION The terms x 2 and –6 have no common factor. Use the commutative property to rearrange the terms so that you can group terms with a common factor. x 3 – 3x 2 + 2x – 6 x 3 – 6 + 2x – 3x 2 = Rearrange terms. (x 3 – 3x 2 ) + (2x – 6) = Group terms. x 2 (x – 3 ) + 2(x – 3) = Factor each group. (x – 3)(x 2 + 2) = Distributive property

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Factor by grouping EXAMPLE 3 CHECK Check your factorization using a graphing calculator. Graph y and y Because the graphs coincide, you know that your factorization is correct. 1 = (x = (x – 3)(x 2 + 2). 2 6 + 2x = x 3 – – 3x2 – 3x2

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GUIDED PRACTICE for Examples 1, 2 and 3 Factor the expression. 1. x(x – 2) + (x – 2) = (x – 2) (x + 1) 2. a 3 + 3a 2 + a + 3 = (a + 3)(a 2 + 1) 3. y 2 + 2x + yx + 2y = (y + 2)( y + x )

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Do Now: Pass out calculators. Pick up a homework answer key from the table and make corrections to your homework.

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To Factor COMPLETELY… 1.Factor out greatest common monomial factor (if possible). Example: 3x 2 + 6x = 3x (x + 2) 2. Look for a difference of two squares or a perfect square trinomial. Example: x 2 + 4x + 4 = (x + 2) 2 3. Factor the trinomial into a product of factors. Example: 3x 2 – 5x – 2 = (3x + 1)(x – 2) 4. Factor a polynomial with four terms by grouping. Example: x 3 + x – 4x 2 – 4 = (x 2 + 1)(x – 4)

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To Factor COMPLETELY… A polynomial is factored completely when there is no other possible way to factor it. It should be written as a product of unfactorable polynomials with integer coefficients.

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Factor completely EXAMPLE 1 Factor the polynomial completely. a. n 2 + 2n – 1 SOLUTION a. The terms of the polynomial have no common monomial factor. Also, there are no factors of – 1 that have a sum of 2. This polynomial cannot be factored.

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Factor completely EXAMPLE 2 Factor the polynomial completely. b. 4x 3 – 44x 2 + 96x SOLUTION b. 4x 3 – 44x 2 + 96x = 4x(x 2 – 11x + 24) Factor out 4x. = 4x(x– 3)(x – 8) Find two negative factors of 24 that have a sum of – 11.

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Factor completely EXAMPLE 2 Factor the polynomial completely. c. 50h 4 – 2h 2 SOLUTION c. 50h 4 – 2h 2 = 2h 2 (25h 2 – 1) Factor out 2h 2. = 2h 2 (5h – 1)(5h + 1) Difference of two squares pattern

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GUIDED PRACTICE for Example 4 Factor the polynomial completely. 1. 3x 3 – 12x = 3x (x + 2)(x – 2) 2. 2y 3 – 12y 2 + 18y = 2y(y – 3) 2 3. m 3 – 2m 2 + 8m = m(m – 4)(m + 2)

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Solve a polynomial equation EXAMPLE 3 Factor out 3x. Solve 3x 3 + 18x 2 = – 24x. 3x 3 + 18x 2 = – 24x Write original equation. 3x 3 + 18x 2 + 24x = 0 Add 24x to each side. 3x(x 2 + 6x + 8) = 0 3x(x + 2)(x + 4) = 0 Factor trinomial. Zero-product property x = 0 or x = – 2 or x = – 4 Solve for x. 3x = 0 or x + 2 = 0 or x + 4 = 0 ANSWER The solutions of the equation are 0, – 2, and – 4.

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GUIDED PRACTICE for Example 5 Solve the equation. 4. w 3 – 8w 2 + 16w = 0 ANSWER 0, 4 5. x 3 –25x 2 = 0 ANSWER 0, 5 + – 6. c 3 – 7c 2 + 12c = 0 ANSWER 0, 3, and 4

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